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A particle of mass 0.1 kg executes SHM under a force F=-10x(N). Speed of particle at mean position is 6m/s. Find its amplitude of oscillations . |
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Answer» SOLUTION :From conservationfo MECHANICAL ENERGY `1/2kA^(2)=1/2mv^(2)` or `A=vsqrt(m/k)=6sqrt(0.1/10)=6/10=0.6m` |
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