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A particle of mass 0.1 kg is subjected to a force which varies with distance as shown in figure. If it starts its journey from rest at x = 0, its velocity at x = 12 m is |
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Answer» `0 m//s` `= (4 xx 10)/2 + 4 xx 10 + (4 xx 10)/(2) = 80 J` According to work - energy theorem , `Delta KE = W_("net")` `:. 1/2 mv^2 - 0 = 80" or " 1/2 xx 0.1 v^2 = 80` or `v = SQRT(1600) = 40 m//s` . |
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