A particle of mass 0.1 kg moving with an initial speed v collides with another particle of same mass kept at rest. If after collision total energy becomes 0.2 J, then the minimum and maximum values of .v. are

A particle of mass 0.1 kg moving with an initial speed v collides with

1.	A particle of mass 0.1 kg moving with an initial speed v collides with another particle of same mass kept at rest. If after collision total energy becomes 0.2 J, then the minimum and maximum values of .v. are
Answer» Solution :In case of perfectly INELASTIC COLLISION the velocity of combined mass will be v/2 `therefore KE=(1)/(2)(2m)((v^(2))/(4))i.e., (0.2)=(1)/(2)(0.2)((v^(2))/(4))` `RARR v=2sqrt(2)m//s`. In case of perfectly elastic collision, first particle STOPS and the second acquires the same velocity v `KE=(1)/(2)mv^(2)i.e., 0.2=(1)/(2)(0.1)v^(2) rArr v=2 m//s` Therefore, minimum value of v is 2 m/s in case of perfectly elastic collision and maximum value of v is `2sqrt(2)` m/s in case of perfectly inelastic collision.