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A particle of mass 0.25 kg vibrates with a period of 2 s. It its greatest displacement is 0.4 m, its maximum velocity in m/s will beA. `pi//5`B. `pi//10`C. `2pi//5`D. `pi//2` |
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Answer» Correct Answer - C `v_(m)=Aomega` `=0.4xx(2pi)/(T)=0.4xx(2pi)/(2)=(4pi)/(10)=(2)/(5)pi` |
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