A particle of mass 0.40kg moving initially with a constant speed of 10

1.	A particle of mass 0.40kg moving initially with a constant speed of 10ms-1 to the north is subject to a constant force of 8.0N directed towards the south for 30s. Take the instant the force is applied to be t = 0, the position of the particle at that time to be x = 0, and predict its position at t = - 5s, 25s, 100s.
Answer» a = - 20ms^-2 0 ≤ t ≤ 30s t = - 5s: x = ut = -10 × 5 = - 50m t = 25s : x = ut + (½) at² = (10 × 25 - 10 × 625)m = - 6km t = 100s : First consider motion up to 30s x₁ = 10 × 30 -10 × 900 = - 8700m At t = 30s, v = 10 - 20 × 30 = - 590ms^-1 For motion from 30s to 100s : x₂ = 590 × 70 = - 41300m x = x₁ + x₂ = - 50km

A particle of mass 0.40kg moving initially with a constant speed of 10ms-1 to the north is subject to a constant force of 8.0N directed towards the south for 30s. Take the instant the force is applied to be t = 0, the position of the particle at that time to be x = 0, and predict its position at t = - 5s, 25s, 100s.

Answer»

a = - 20ms^-2 0 ≤ t ≤ 30s

t = - 5s:

x = ut = -10 × 5 = - 50m

t = 25s :

x = ut + (½) at² = (10 × 25 - 10 × 625)m = - 6km

t = 100s :

First consider motion up to 30s

x₁ = 10 × 30 -10 × 900 = - 8700m

At t = 30s, v = 10 - 20 × 30 = - 590ms^-1

For motion from 30s to 100s :

x₂ = 590 × 70 = - 41300m x = x₁ + x₂ = - 50km

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