1.

A particle of mass 1 kg is executing SHM with an amplitude of 1m and time period pis. Calculate the kinetic energy of the particle at the moment when the displacement is 0.8m from mean position?

Answer»

SOLUTION :`omega= (2pi)/(T)= (2pi)/(pi)= 2s` we have `V= omegasqrt(A^(2)-x^(2))= 2sqrt((1)^(2)-(0.8)^(2))= 2 xx 0.6 = 1.2m//s`
`"KINETIC ENERGY"= (1)/(2)mv^(2)= (1)/(2)xx 1xx (1.2)^(2)= 0.72J`


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