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A particle of mass 1 kg is executing SHM with an amplitude of 1m and time period pis. Calculate the kinetic energy of the particle at the moment when the displacement is 0.8m from mean position? |
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Answer» SOLUTION :`omega= (2pi)/(T)= (2pi)/(pi)= 2s` we have `V= omegasqrt(A^(2)-x^(2))= 2sqrt((1)^(2)-(0.8)^(2))= 2 xx 0.6 = 1.2m//s` `"KINETIC ENERGY"= (1)/(2)mv^(2)= (1)/(2)xx 1xx (1.2)^(2)= 0.72J` |
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