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A particle of mass 1 kg is executing SHM with an amplitude of 1m and time period pis. Calculate the kinetic energy of the particle at the moment when the displacement is 0.8m from mean position?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`omega= (2pi)/(T)= (2pi)/(pi)= 2s` we have `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>= omegasqrt(A^(2)-x^(2))= 2sqrt((<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)^(2)-(0.8)^(2))= 2 xx 0.6 = 1.2m//s` <br/> `"<a href="https://interviewquestions.tuteehub.com/tag/kinetic-533291" style="font-weight:bold;" target="_blank" title="Click to know more about KINETIC">KINETIC</a> <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a>"= (1)/(2)mv^(2)= (1)/(2)xx 1xx (1.2)^(2)= 0.72J`</body></html>


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