1.

A particle of mass 1 kg is executing SHM with an amplitude of 1 m and time period pis. Calculate the kinetic energy of the particle at the moment when the displacemen is 0.8 m from mean position?

Answer»

SOLUTION :`OMEGA=(2pi)/T=(2pi)/(pi)=2s` we have `v=omegasqrt(A^(2)-x^(2))`
`=2sqrt((1)^(2)-(0.8)^(2))=2xx0.6=1.2m//s`
KINETIC energy `=1/2mv^(2)=1/2xx1xx(1.2)^(2)=0.72J`


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