A particle of mass 1 kg is moving along the line y = x + 2 (here x and y are in metres) with speed 2 m/s. The magnitude of angular momentum of particle about its origin is

A particle of mass 1 kg is moving along the line y = x + 2 (here x and

1.	A particle of mass 1 kg is moving along the line y = x + 2 (here x and y are in metres) with speed 2 m/s. The magnitude of angular momentum of particle about its origin is
Answer» `4 kg m^(2) s^(-1)` `2 SQRT2 kg m^(2) s^(-1)` `4 sqrt2 kg m^(2) s^(-1)` `2 kg m^(2) s^(-1)` Solution :The GIVEN eqn. of the line is `y = X + 2` At x = -2 , y = 0 and at x = 0 , y = 2 The line is drawn as shown in the figure . Length of perpendicular drawn from origin to this line is `ON = r_(1) = (0 + 0 + 2)/(SQRT(1 ^(2) + 1^(2)) = sqrt2` Angular momentum of particle about `L = m vr_(bot) = (1) (2)sqrt2 = 2 sqrt2 kg m^(2) s^(-1)`