A particle of mass 1 kg is projected upwards with velocity 60ms^(-1). Another particle of mass 2kg is just dropped from a certain height. After 2s, match the following. [Take, g =10 ms^(-2)] {:("column1","column2"),("Accelertion of CM","P Zero"),("B Velocity of CM","Q 10 SI unit"),("C Displacement of CM","20 SI unit"),("-","S None"):}

A particle of mass 1 kg is projected upwards with velocity 60ms^(-1).

1.	A particle of mass 1 kg is projected upwards with velocity 60ms^(-1). Another particle of mass 2kg is just dropped from a certain height. After 2s, match the following. [Take, g =10 ms^(-2)] {:("column1","column2"),("Accelertion of CM","P Zero"),("B Velocity of CM","Q 10 SI unit"),("C Displacement of CM","20 SI unit"),("-","S None"):}
Answer» SOLUTION :From `a_(CM)= ((m_(1)a_(1) + m_(2)a_(2))/(m_(1) + m_(2))` `=((1)(-10)+2(-10))/(3) = -10 MS^(-2)` `u_(CM) = ((m_(1)u_(1) + m_(2)u_(2))/(m_(1) + m_(2)`, after 2s `=((1)(40)+(2)(20))/(3) = (40+40)/3 = 80/3`