InterviewSolution
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InterviewSolution
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A particle of mass 1 kg is projected upwards with velocity `60ms^(-1)`. Another particle of mass 2kg is just dropped from a certain height. After 2s, match the following. [Take, g `=10 ms^(-2)]``{:("column1","column2"),("Accelertion of CM","P Zero"),("B Velocity of CM","Q 10 SI unit"),("C Displacement of CM","20 SI unit"),("-","S None"):}` |
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Answer» Correct Answer - A `rightarrow` q, B`rightarrow`p, C `rightarrow` r From `a_(CM)= ((m_(1)a_(1) + m_(2)a_(2))/(m_(1) + m_(2))` `=((1)(-10)+2(-10))/(3) = -10 ms^(-2)` `u_(CM) = ((m_(1)u_(1) + m_(2)u_(2))/(m_(1) + m_(2)`, after 2s `=((1)(40)+(2)(20))/(3) = (40+40)/3 = 80/3` |
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