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InterviewSolution
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A particle of mass 1 kg is released from rest at a point where gravitational potential is 5 J/kg. After some time, it passes through a point B with a speed of 1 m/s. What is the gravitational potential at B ? |
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Answer» As the particle moves from A to B, its kinetic energy increases. So, its potential energy at B must be less than its potential energy at A. By conservation of mechanical energy energy we obtain `K_(A)+U_(A)=K_(B)+U_(B)` `0+U_(A)=(1)/(2)xx1xx(1)^(2)+U_(B)` `rArr U_(A)-U_(B)=0.5` Dividing both sides by mass of the particle `(U_(A)-U_(B))/(m)=(0.5)/(1)` J/kg. `rArr V_(A)-V_(B)=0.5` J/kg. `rArr V_(B)=4.5 J//kg (because V_(A)=5 J//kg)` |
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