A particle of mass 10^(-2)kg, under the action of a force F(x) = - (k)/(2x^(2)) , is in motion along the positive x-direction. At time t = 0, the position of the particle is x = 1.0 m, and velcoity = 0, If k = 10^(-2) Ncdot m^(2),find the velocity when the particle is at x = 0.50 m.

A particle of mass 10^(-2)kg, under the action of a force F(x) = - (k)

1.	A particle of mass 10^(-2)kg, under the action of a force F(x) = - (k)/(2x^(2)) , is in motion along the positive x-direction. At time t = 0, the position of the particle is x = 1.0 m, and velcoity = 0, If k = 10^(-2) Ncdot m^(2),find the velocity when the particle is at x = 0.50 m.
Answer» ANSWER :`-1 m CDOT s^(-1)`; (II) 1.479 s