A particle of mass `10^(-4) kg` and charge `5muC` id thrown at a speed of `20m//s` against a uniform electric field of strength `2xx10^(5) NC^(-1)`. How much distance will it travel before coming to rest momentarilly ?

A particle of mass `10^(-4) kg` and charge `5muC` id thrown at a speed

1.	A particle of mass `10^(-4) kg` and charge `5muC` id thrown at a speed of `20m//s` against a uniform electric field of strength `2xx10^(5) NC^(-1)`. How much distance will it travel before coming to rest momentarilly ?
Answer» Here, `m = 10^(-4) kg ,` `q = 5 muC = 5xx10^(-6) C , v = 20 ms^(-1),` `E = 2xx10^(5) N//C` Force on charged particle `F = qE = 5xx10^(-6)xx2xx10^(5) = 1N` As particle is thrown against the field, so `a = - (F)/(m) = - (1)/(10^(-4)) = - 10^(4) m//s^(2)` From `v^(2) - u^(2) = 2as` `:. (0)^(2) -(20)^(2) = 2 (-10^(4))s` `:. s = 0*023m`

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A particle of mass `10^(-4) kg` and charge `5muC` id thrown at a speed of `20m//s` against a uniform electric field of strength `2xx10^(5) NC^(-1)`. How much distance will it travel before coming to rest momentarilly ?

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