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A particle of mass 10 g moves along a circle of radius `6.4` cm with a constant tangential acceleration. What is the magnitude of this acceleration. What is the magnitude of this acceleration, if the kinetic energy of the particle becomes equal to `8xx10^(-4)`J by the end of the second revolution after the beginning of the motion?A. `0.15" ms"^(-2)`B. `0.18" ms"^(-2)`C. `0.2" ms"^(-2)`D. `0.1" ms"^(-2)` |
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Answer» Correct Answer - D (d) `W_("Tengential")=DeltaKE=K_(f)-K_(i)=K_(f)-0` `(ma_(T))xx5=8xx10^(-4)` `a_(T)=(8xx10^(-4))/(10^(-2)(2pirxx2))=(2xx10^(-2))/(pixx2pixx10^(-2))=0.1 ms^(-2)` |
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