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| 1. |
A particle of mass `1kg` is projected at an angle of `theta=pi//4` from horizontal with a muzzle velocity of `20 m//s`. A long slender rod of mass `5kg` and length `30 m` is suspended vertically from a point at the same horizontal leves as that of point of projection and at a distance of `60m` from the projection point. The rod can rotate freely. If collision occurs, it is perfectly plastic. (`g=10m//s^(2)`) If the rod tilts to an angle `theta` after collision, then A. `theta=0^(@)`B. `theta=cos^(-1)(40//42)`C. `theta=cos^(-1)(41//42)`D. `theta=cos^(-1)(27//28)` |
| Answer» Hint : First find the point where collision occurs using equation of trajectory. Then use conservation of angular momentum. After collision energy conservation is valid. | |