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A particle of mass = 2 kg executes SHM in xy-plane between points A and B under action of force →F=Fx^i+Fy^j. Minimum time taken by particle to move from A to B is 1 sec. At t= 0 the particle is at x = 2 and y = 2. Then Fx as function of time is |
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Answer» A particle of mass = 2 kg executes SHM in xy-plane between points A and B under action of force →F=Fx^i+Fy^j. Minimum time taken by particle to move from A to B is 1 sec. At t= 0 the particle is at x = 2 and y = 2. Then Fx as function of time is
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