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A particle of mass 2kg is moving in free space with velocity `vecv_0=(2hati-3hatj+hatk)m//s` is acted upon by force `vecF=(2hati+hatj-2hatk)N`. Find velocity vector of the particle 3s after the force starts acting. |
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Answer» `vecp_f=vecp_i+vecI_mp rarr mvecv_f=mvec v_0+vecFDeltat` Substituting given value, we have `2vecv_f=2(2hat i-3hatj+hatk)+(2hati+hatj-2hatk)xx3=10hati-3hatj-4hatk` `vecv_f=(5hati-1.5hatj-2hatk)m/s` |
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