InterviewSolution
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InterviewSolution
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A particle of mass 4 m which is at rest explodes into three fragments. Two of the fragments each of mass m are found to move with a speed v each in mutually perpendicular directions. The total energy released in the process of explosion is ............A. `(2//3)mv^(2)`B. `(3//2) mv^(2)`C. `(4//3) mv^(2)`D. `(3//4) mv^(2)` |
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Answer» Correct Answer - B `mv_(1)+mvj+2mv_(3)=0` `vec(v)_(3)=-((vi+vj))/2=-v/2(i+j)=-v/(sqrt(2))` `k_(f)=1/2 mv^(2)+1/2 mv^(2)+1/2 2m(v^(2))/2` `k_(f)=(3mv^(2))/2` |
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