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A particle of mass 50 g is projected horizontally from the top of a tower of height 50 m with a velocity `20m//s`. If `g=10m//s^(2)`, then find the :-A. Velocity at the instant t=2 sB. Position at the instant t=3 sC. Velocity just before hitting the groundD. Change in velocity in 2 s

Answer» Correct Answer - A::B::C::D


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