InterviewSolution
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InterviewSolution
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A particle of mass `m` and carrying charge `-q_(1)` is moving around a charge `+q_(2)` along a circular path of radius `r` period of revolution of the charge `-q_(1)` about `+q_(2)` isA. `4sqrt((pi^(3)epsilon_(0)mr^(3))/(q_(1)q_(2)))`B. `sqrt((pi^(3)epsilon_(0)mr^(3))/(q_(1)q_(2)))`C. `2sqrt((pi^(3)epsilon_(0)mr^(3))/(q_(1)q_(2)))`D. `3sqrt((pi^(3)epsilon_(0)mr^(3))/(q_(1)q_(2)))` |
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Answer» Correct Answer - a Suppose that the charge `-q_(1)` moves around the charge `q_(2)` along a circular path of radius `r` with spedd `v`. The necessary centripetal force is provided by the electronic force of attraction between the two charges i.e., `(1)/(4piepsilon_(0)).(q_(1)xxq_(2))/(r^(2))= (mv^(2))/(r)` Or `v= (1/(4piepsilon_(0)).(q_(1)xxq_(2))/(mr))^(1//2)` If `T` is period of revolution of the charge `-q_(1)` about `q_(2)` then `T=(2pir)/(v)` Subsituting for `v` we get `T = sqrt((16pi^(3)epsilon_(0)mr^(3))/(q_(1)q_(2)))` |
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