An electric dipole is placed in a uniform electric field `vec(E )` of magnitude `40N//C`. Graph shows the magnitude of the square on the dipole versus the angle `theta` between the field `vec(E )` and the dipole moment `vec(p)`. The magnitude of dipole moment `vec(p)` is equal to: A. `1.25xx10^(-28)C-m`B. `2.0xx10^(-25)C-m`C. `2.5xx10^(-28)C-m`D. `5.0xx10^(-28)C-m`

An electric dipole is placed in a uniform electric field `vec(E )` of

1.	An electric dipole is placed in a uniform electric field `vec(E )` of magnitude `40N//C`. Graph shows the magnitude of the square on the dipole versus the angle `theta` between the field `vec(E )` and the dipole moment `vec(p)`. The magnitude of dipole moment `vec(p)` is equal to: A. `1.25xx10^(-28)C-m`B. `2.0xx10^(-25)C-m`C. `2.5xx10^(-28)C-m`D. `5.0xx10^(-28)C-m`
Answer» Correct Answer - a `vec(tau)=vec(p)xxvec(E )` `tau_(max)=pEimplies 50xx10^(-28)= p.40` `implies p=1.25xx10^(-28)C-m`

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An electric dipole is placed in a uniform electric field `vec(E )` of magnitude `40N//C`. Graph shows the magnitude of the square on the dipole versus the angle `theta` between the field `vec(E )` and the dipole moment `vec(p)`. The magnitude of dipole moment `vec(p)` is equal to: A. `1.25xx10^(-28)C-m`B. `2.0xx10^(-25)C-m`C. `2.5xx10^(-28)C-m`D. `5.0xx10^(-28)C-m`
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