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A particle of mass `m` and charge `q` travelling at a velocity `v` along `x`-axis at time `t=0`. It enters a region in which electric field, `E` is present along `z`-axis and magnetic field, `B` is present along `y`-axis. The distance covered upto time `t=0.2xx10^(-1) sec,` along `x`-axis is `v//50` (in meters). find the value of `v`: A. `(50 E)/B`B. `E/(50 B)`C. `E/(20B)`D. `E/B` |
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Answer» Correct Answer - D Distance covered in time `t=v//50` (given) From, `x=vt=vxx0.02=v//50` Thus, acceleration of particle `=0` So, `F_("net")=0` `F_(e)=F_(m)` `qE=qvB` `v=(E )/(B)` |
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