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A particle of mass `M` at rest dacays into two particle of masses `m_(1)` and `m_(2) `having non zero velocity . The ratio of the de Broglie wavelength . The ratio of the de Broglie wavelength of the particle `lambda , _(1) // lambda_(2)` isA. `m_(1)/m_(2)`B. `m_(2)/m_(1)`C. `1:1`D. `sqrt(m_(2)/m_(1))` |
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Answer» Correct Answer - C `lambda=h/p` and from conservation of linear momentum both particles will have same magnitude of linear momentum after decay. |
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