A particle of mass m, collides with another stationary particle of mass M. If the particle m stops just after collision, then the coefficient of restitution for collision is equal toA. 1B. `m/M`C. `(M-m)/(M+m)`D. `m/(M+m)`

A particle of mass m, collides with another stationary particle of mas

1.	A particle of mass m, collides with another stationary particle of mass M. If the particle m stops just after collision, then the coefficient of restitution for collision is equal toA. 1B. `m/M`C. `(M-m)/(M+m)`D. `m/(M+m)`
Answer» Correct Answer - B As net horizontal force acting on the system is zero, hence, momentum must remain conserved. Hence, `mu + 0 = 0 +Mv_(2)` As per definition, `e = \|(v_(2)-v_(1))\|/\|(u_(2)-u_(1))\| = \|(v_(2)-0)/(0-u)\|` `v_(2)/u= (mu)/(M)/u = m/M`

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A particle of mass m, collides with another stationary particle of mass M. If the particle m stops just after collision, then the coefficient of restitution for collision is equal toA. 1B. `m/M`C. `(M-m)/(M+m)`D. `m/(M+m)`

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