

InterviewSolution
Saved Bookmarks
1. |
A particle of mass m executes simple harmonic motion with amplitude a and frequency v. The average kinetic energy during its motion from the position of equilinrium to the end is.A. `pi^(2)mn^(2)A^(2)`B. `2pi^(2)mn^(2)A^(2)`C. `(pi^(2)mn^(2)A^(2))/(2)`D. zero |
Answer» Correct Answer - A `(ke_("max")+0)/(2)=(1)/(2) ((1)/(2)m omega^(2) A^(2))` `=(1)/(4) m (2pin)^(2)A^(2)` `=pi^(2)mn^(2)A^(2)`. |
|