1.

A particle of mass m, initially at rest is acted upon by a variable force F for a brief interval of time T. It begins to move with a velocity u after the force stops acting. F is shown in the graph as a function of time. The curve is a semicircle. Then

Answer»

`u=(piF_(0)^(2))/(2m)`
`u=(piT^(2))/(8M)`
`u=(piF_(0)T)/(4m)`
`u=(piF_(0)T)/(2m)`

SOLUTION :IMPULSE = Area of SEMI circle


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