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A particle of mass `m` , initially at rest , is acted upon by a variable force `F` for a brief interval of time `T`. It begins to move with a velocity `u` after the forrce stops acting . `F` is shown in the graph as a function of time. The curve is a semicircle. A. `u = (pi F_(0)^(2))/(2m)`B. `u = (pi T^(2))/(8m)`C. `u = (pi F_(0) T)/( 4m)`D. `(F_(0) T)/(2 m)` |
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Answer» Correct Answer - C Area of `F-t` graph ` = (pi F_(0) T)/(4)` (Area of ellipse `= pi ab)` `Delta p = (pi F_(0) T)/(4)` `m( u - 0) = (pi F_(0) T)/(4) rArr u = (pi F_(0) T)/(4m)` |
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