1.

A particle of mass m is executing oscillations about the origin on the x-axis. Its potential energy is V(x)=kx^(2). Where k is a positive constant. If the amplitude of oscillation is a, then its time period T is……………

Answer»

Proportional to `(1)/(sqrt(a))`
independent of a
proportional to `sqrt(a)`
proportional to `a^(3//2)`

SOLUTION :SINCE `V(x)=Kx^(2)`, the motion is simple harmonic. In SHM, the time PERIOD is independent of the amplitude of oscillation.


Discussion

No Comment Found