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A particle of mass m is executing SHM about its mean position. The total energy of the particle at given instant isA. `(pi^(2)mA^(2))/(T^(2))`B. `(2pi^(2)mA^(2))/(T^(2))`C. `(4pi^(2)mA^(2))/(T^(2))`D. `(8pi^(2)mA^(2))/(T^(2))` |
Answer» Correct Answer - B `E=(1)/(2)momega^(2)A^(2)=(m4pi^(2)A^(2))/(T^(2))=(4pi^(2)mA^(2))/(T^(2))` |
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