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A particle of mass M is moving in a circular path of radius 2m. Its speed depends on the distance covered by the particle from the hegining according to the relation c = ks, where k is a positive constant and s is the distance covered. The power of force acting on teh particle when the particle has covered half of the circular path will be :A. `pi^(2)k^(2)M`B. `2pi^(2)k^(3)M`C. `4pi^(2)k^(3)M`D. `8pi^(2)k^(2)M` |
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Answer» Correct Answer - C P = Fv `S = pi R` `v = ks rArr v = k.pi R` `a = v (dv)/(ds) = ks.k = k^(2)s` `s = piR` `a = k^(2).piR rArr F = mk^(2). pi R` `P = mk^(2) pi R . kpi R = mk^(3) pi^(2)R^(2)` `M = 4 pi^(2)k^(3)m` |
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