A particle of mass m is moving in a horizontal circle of radius r under a centripetal force given by((-K)/(r^(2))) where k is a constant then,

A particle of mass m is moving in a horizontal circle of radius r unde

1.	A particle of mass m is moving in a horizontal circle of radius r under a centripetal force given by((-K)/(r^(2))) where k is a constant then,
Answer» the total ENERGY of the particle is`((-K)/(2R))` the total energy of the particle is `((k)/(r))` the total energy of the particle is `((k)/(2r))` the total energy of the particle is `(-(k)/(r))` Solution :(a)