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A particle of mass `m` is moving in a plane along a circular path of radius `r`. Its angular momentum about the axis of rotation is `L`. The centripetal force acting on the particle is.A. `(L^(2))/(mr)`B. `(L^(2))/(mr^(2))`C. `(L^(2))/(mr^(3))`D. `(L)/(mr^(2))` |
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Answer» Correct Answer - C `L=mvr thereforev=(L)/(mr)` `F=(mv^(2))/(r)=(L^(2))/(mr^(3))` |
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