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Velocity of a particle moving in a curvilinear path varies with time as `v=(2t hat(i)+t^(2) hat(k))m//s`. Here t is in second. At `t=1` sA. acceleration of particle is `8 m//s^(2)`B. tangential acceleration of particle is `(6)/(sqrt(5)) m//s^(2)`C. radial acceleration of particle is `(2)/(sqrt(5))m//s^(2)`D. radius of curvature to the path is `(5 sqrt(5))/(2)m` |
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Answer» Correct Answer - B::C::D |
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