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A particle of mass `m` is moving in a plane along a circular path of radius `r`. Its angular momentum about the axis of rotation is `L`. The centripetal force acting on the particle is.A. `(L^2)/(mr)`B. `(L^2 m)/( r)`C. `(L^2)/(mr^3)`D. `(L^2)/(mr^2)` |
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Answer» Correct Answer - C ( c) `L = mvr rArr v = (L)/(mr)` `F_c = (mv^2)/(r) = (m)/(r) ((L)/(mr))^2 = (L^2)/(mr^3)`. |
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