InterviewSolution
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InterviewSolution
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A particle of mass ‘m’ is moving in circular path of constant radius ‘r’ such that centripetal acceleration is varying with time ‘t’ as K2 r t2 where K is a constant. The power delivered to the particle by the force acting on it is(A) m2 K2 r2 t2 (B) mK2 r2 t (C) m K2 r t2 (D) m K r2 t |
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Answer» Answer is (B) mK2 r2 t Centripetal acceleration \(\frac{v^2}{r}\) = K2t2r ∴ v = K t r acceleration, a = \(\frac{dv}{dt}\) = \(\frac{d}{dt}\)(Ktr) = kr F = m x a and P = F x v = mKr x Ktr = mK2 t r2 |
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