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A particle of mass M is placed at the centre of a uniform spherical shell of equal mass and radius a. Find the gravitational potential at a point P at a distance a/2 from the centre. |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The gravitational potential at the point P <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to the particle at the centre is <br/> `V_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) = -(<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/(a//2) = -(2GM)/(a)` <br/> The potential at P due to the <a href="https://interviewquestions.tuteehub.com/tag/shell-11505" style="font-weight:bold;" target="_blank" title="Click to know more about SHELL">SHELL</a> is `V_(2) = -(Gm)/(a)` <br/> The net potential at P is `V_(1) = V_(2) = -(3Gm)/(a)`</body></html> | |