A particle of mass m is projected with a velocity v=kve(k<1) from the surface of the earth. (ve= escape velocity). The maximum height above the surface reached by the particle is -R is the radius of earth.

A particle of mass m is projected with a velocity v=kve(k<1) from the

1.	A particle of mass m is projected with a velocity v=kve(k<1) from the surface of the earth. (ve= escape velocity). The maximum height above the surface reached by the particle is -R is the radius of earth.
Answer» A particle of mass $m$ is projected with a velocity $v = k v_{e} (k < 1)$ from the surface of the earth. $(v_{e} =$ escape velocity $)$ . The maximum height above the surface reached by the particle is - $R$ is the radius of earth.

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A particle of mass m is projected with a velocity v=kve(k&lt;1) from the surface of the earth. (ve= escape velocity). The maximum height above the surface reached by the particle is -R is the radius of earth.

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A particle of mass m is projected with a velocity v=kve(k<1) from the surface of the earth. (ve= escape velocity). The maximum height above the surface reached by the particle is -R is the radius of earth.