1.

A particle of mass 'm' is projected with an initial velocity u at an angle 'theta' to horizontal. The torque due to gravity on projectile at maximum height about the point projection is

Answer»

`("mgu"^(2)SIN2THETA)/(2)`
`"MG u"^(2)sin2theta`
`("mgu"^(2)SINTHETA)/(2)`
`1/2"mu"^(2)sin2theta`

Answer :D


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