1.

A particle of mass m is rotated in the horizontal xy plane along a circular curves of radius r with angular speed omega radian per second. The rotation is opposite to that of hands of aclock

Answer»

The ANGULAR momentum of the particle about an axis passing through CENTRE of path is `mr^(2)omegahat(k)`
Same as A except that `mr^(2)omegahat(k)` accompanies a minus sign
Said angular momentum acts along positive z axis through the centre of circular path
Magnitude of said angular momentum is `1//2mr^(2)OMEGA`

ANSWER :A::C


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