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A particle of mass m moves in the potential energy U shoen above. The period of the motion when the particle has total energy E isA. `2pisqrt((m)/(k))+4sqrt((2E)/(mg^2))`B. `2pisqrt((m)/(k))`C. `pisqrt((m)/(k))+2sqrt((2E)/(mg^2))`D. `2sqrt((2E)/(mg^2))` |
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Answer» Correct Answer - C For `xlt0` `F=-(dU)/(dx)=-kx` `ma=-kx` or `a=-(k)/(m)x` `-omega_1^2x=-(k)/(m)x` `omega_1=sqrt((k)/(m))` `T_1=2pisqrt((m)/(k))` For `xgt0` `U=mgx` `F=-(dv)/(dx)=-mg` But `E=(1)/(2)mv_0^2` `v_0=sqrt((2E)/(m))` It is speed at lowest point `T_2=(2v_0)/(g)=(2)/(g)sqrt((2E)/(m))` `T=(T_1)/(2)+T_2=pisqrt((m)/(k))+(2)/(g)sqrt((2E)/(m))` |
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