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The oscillations represented by curve 1 in the graph are expressed by equation`x=Asinomegat.` The equation for the oscillation represented by curve `2` is expressed asA. `x=2Asin(omegat-(pi)/(2))`B. `x=2Asin(omegat+(pi)/(2))`C. `x=-2Asin(omegat-(pi)/(2))`D. `x=Asin(omegat-(pi)/(2))` |
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Answer» Correct Answer - A Oscillations represented by curve 2 lags in phase by `(pi)/(2)` and the periods are same. Amplitude of curve 2 is double that of 1. Put `t=0` then `x=2Asin(0-(pi)/(2))=-2A` |
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