1.

A particle of mass m moving in a circular path of constant radius r such that its centripetal acceleration a_(c) is varying with time t as a_(c)= k^(2)rt^(2), where k is a constant.

Answer»

Solution :As `a_(c )=(V^(2)//R)` so `(v^(2)//r)=k^(2)rt^(2)`
KINETIC energy K `= (1)/(2)mv^(2)=(1)/(2)mk^(2)r^(2)t^(2)`
Now by work - Energy Theorem
`W=Delta K = (1)/(2)mk^(2)r^(2)t^(2)-0rArr P =(dW)/(dt)`
`RARR P=(d)/(dt)=(1)/(2)mk^(2)r^(2)t^(2)=mk^(2)r^(2)t`


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