1.

A particle of mass m moving towards the east with speed v collides with another particle of the same mass and same speed v moving towards the north. If the two particles stick to each other, the new particle of mass 2m will have a speed of

Answer»

`v`
`v/2`
`v/(SQRT2)`
`vsqrt(2)`

Solution :It is a CASE of perfectly inelastic collision.
According to law of CONSERVATION of linear momentum, we get
`m^2 v^2 + m^2v^2 = (2 mV)^(2)`
where V is the common VELOCITY after the collision.
SOLVING , we get , `V = v/(sqrt2)`.


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