A particle of mass m moving with a speed v hits elastically another stationary particle of mass 2m on a smooth horizontal circular tube of radius r. The time in which the next collision wll take place is equal to

A particle of mass m moving with a speed v hits elastically another st

1.	A particle of mass m moving with a speed v hits elastically another stationary particle of mass 2m on a smooth horizontal circular tube of radius r. The time in which the next collision wll take place is equal to
Answer» Solution :Relative VELOCITY of separation =relative velocity of approach = v `THEREFORE` TIME of NEXT collision = `(2pi R)/(v)`