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A particle of mass `m` moving with a speed `v` hits elastically another staionary particle of mass `2m` on a smooth horizontal circular tube of radius `r`. Find the time when the next collision will take place?A. `(2pir)/(v)`B. `(4pir)/(v)`C. `(3pir)/(2v)`D. `pir)/(v)` |
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Answer» Correct Answer - A Relative speed of seperation = relative speed of approach `therefore` Time of next collision = `(2pir)/v` |
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