1.

A particle of mass m moving with velocity v_(0) collides with sphere of same mass at rest , as shown. If the surface of contact is smooth and the collision is elastic, find the velocities of particle and sphere after the collision.

Answer»

SOLUTION :The PARTICLE and SPHERE will perpendicular after the collision.

By the momentum conservation:
x-ax is: `mv_(0) = mv_(1) cos theta + mv_(2) cos theta(90 - theta)`
`v_(0) = v_(1) cos theta + v_(2) sin theta`(i)
`y-ax is: mv_(1) sin theta - mv_(2) sin (90 - theta)`
`0 = v_(1) sin theta - v_(2) cos theta`
Solving (i) and (II), `v_(1) = v_(0) cos theta , v_(2) = v_(0) sin theta`
`cos theta = (1)/(2) , sin theta = (sqrt(3))/(2)`
`v_(1) = (v_(0))/(2) , v_(2) = (sqrt(3) v_(0))/(2)`



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