Saved Bookmarks
| 1. |
A particle of mass ‘m’ moving with velocity ‘v’ collides in elastically with a stationary particle of mass ‘2m’. The speed of the system after collision will be – (1) ν/2(2) 3ν (3) ν/3(4) 3ν |
|
Answer» Answer is (3) ν/3 m1ν1 + 0 = (m1 + m2)ν’ ⇒ ν’ = mν/(m + 2m) = ν/3 |
|