A particle of specific charge α starts moving from the origin under the action of an electric field →E=E0^i and magnetic field →B=B0^k. Its velocity at (x0,y0,0) is (4^i+3^j). The value of x0 is

A particle of specific charge α starts moving from the origin under t

1.	A particle of specific charge α starts moving from the origin under the action of an electric field →E=E0^i and magnetic field →B=B0^k. Its velocity at (x0,y0,0) is (4^i+3^j). The value of x0 is
Answer» A particle of specific charge $α$ starts moving from the origin under the action of an electric field $\to E = E_{0}^i$ and magnetic field $\to B = B_{0}^k$ . Its velocity at $(x_{0}, y_{0}, 0)$ is $(4^i + 3^j)$ . The value of $x_{0}$ is

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A particle of specific charge α starts moving from the origin under the action of an electric field →E=E0^i and magnetic field →B=B0^k. Its velocity at (x0,y0,0) is (4^i+3^j). The value of x0 is

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