A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x)=βx−2n ,where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by :

A particle of unit mass undergoes one-dimensional motion such that its

1.	A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x)=βx−2n ,where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by :
Answer» A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to $v (x) = β x^{- 2 n}$ ,where $β$ and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by :

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A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x)=βx−2n ,where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by :

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