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A particle oscillate according to y= 7 sin 0.5 pi t. Time taken by particle from equilibrium position to maximum displacement is………. |
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Answer» Solution :COMPARING equation `y= 7sin 0.5 pi t` to general differential equation `y= A sin (OMEGA t)` Amplitude A= 7 unit Angular frequency `omega = 0.5 pi` unit `therefore (2PI)/(T) = (pi)/(2)` `therefore T= 4` unit. |
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