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A particle oscillate according to y= 7 sin 0.5 pi t. Time taken by particle from equilibrium position to maximum displacement is……….

Answer»

Solution :COMPARING equation `y= 7sin 0.5 pi t` to general differential equation `y= A sin (OMEGA t)`
Amplitude A= 7 unit
Angular frequency `omega = 0.5 pi` unit
`therefore (2PI)/(T) = (pi)/(2)`
`therefore T= 4` unit.


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